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Three Dimensional Geometry

Question
CBSEENMA12033269

Find a vector equation of the line through the points A (3, 4, – 7) and B (1, – 1, 6).

Solution
The line passes through the points A (3, 4, – 7), B (1, – 1, 6)
therefore space space space space straight a with rightwards arrow on top space equals space 3 straight i with hat on top space plus space 4 straight j with hat on top space minus space 7 straight k with hat on top comma space space space space straight b with rightwards arrow on top space equals space straight i with hat on top space minus space straight j with hat on top space plus space 6 space straight k with hat on top
where straight a with rightwards arrow on top comma space straight b with rightwards arrow on top are position vectors of A and B respectively.
therefore     straight b with rightwards arrow on top space minus space straight a with rightwards arrow on top space equals space open parentheses straight i with hat on top space minus space straight j with hat on top space plus space 6 straight k with hat on top close parentheses space minus space open parentheses 3 space straight i with hat on top space plus space 4 space straight j with hat on top space minus space 7 space straight k with hat on top close parentheses space equals space minus 2 space straight i with hat on top space minus space 5 space straight j with hat on top space plus space 13 space straight k with hat on top
Let straight r with rightwards arrow on top be the position vector of any point on the given line. 
∴     the vector equation of the line is
straight r with rightwards arrow on top space equals space straight a with rightwards arrow on top space plus space straight lambda open parentheses straight b with rightwards arrow on top space minus space straight a with rightwards arrow on top close parentheses
or   straight r with rightwards arrow on top space equals space open parentheses 3 space straight i with hat on top space plus space 4 space straight j with hat on top space minus space 7 space straight k with hat on top close parentheses space plus space straight lambda space open parentheses negative 2 space straight i with hat on top space minus space 5 space straight j with hat on top space plus space 13 space straight k with hat on top close parentheses where λ is a parameter.