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Differential Equations

Question
CBSEENMA12033108

Solve the  differential equation:
straight x squared dy over dx space equals straight y left parenthesis straight x plus straight y right parenthesis.

Solution
The given differential equation is
straight x squared dy over dx space equals space straight y left parenthesis straight x plus straight y right parenthesis space space space or space space space space dy over dx space equals fraction numerator straight x space straight y space plus space straight y squared over denominator straight x squared end fraction space space space space space space space space... left parenthesis 1 right parenthesis
Put y = v x so that dy over dx space equals space straight v plus dv over dx
therefore space space space from space left parenthesis 1 right parenthesis comma space space straight v plus straight x dv over dx space equals space fraction numerator straight x. space straight v space straight x space plus space straight v squared space straight x squared over denominator straight x squared end fraction
or       straight v plus straight x dv over dx space equals space straight v plus straight v squared
or          straight x dv over dx space equals space straight v squared
Separating the variables, we get,
                     1 over straight v squared dv space equals space 1 over straight x dx space space space space space or space space space straight v to the power of negative 2 end exponent dv space equals space 1 over straight x dx
Integrating,     integral straight v to the power of negative 2 end exponent space dv space equals space integral 1 over straight x dx
therefore space space space space space space fraction numerator straight v to the power of negative 1 end exponent over denominator negative 1 end fraction space equals space log space open vertical bar straight x close vertical bar space plus straight c space space space space space space or space space space space minus 1 over straight v space equals space log space open vertical bar straight x close vertical bar space plus space straight c
therefore space space space space space space fraction numerator negative straight x over denominator straight y end fraction space equals space log space open vertical bar straight x close vertical bar space plus straight c comma space space which space is space required space solution. space

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