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Differential Equations

Question
CBSEENMA12033190

Solve:
dy over dx plus 2 straight y space equals space cos space 3 straight x

Solution
The given differential equation is
       dy over dx plus 2 straight y space equals space cos space 3 straight x
Comparing it with dy over dx plus straight P space straight y space equals space straight Q comma we get,
                 straight P space equals 2 comma space space straight Q space equals space cos space 3 straight x
        integral straight P space dx space equals space integral space 2 space dx space equals 2 straight x
      straight I. straight F. space equals straight e to the power of integral straight P space dx end exponent space equals straight e to the power of 2 straight x end exponent
Solution of given differential equation is
              ye to the power of integral straight P space dx end exponent space equals space integral straight Q space straight e to the power of integral straight P space dx end exponent dx plus straight c
or      ye to the power of 2 straight x end exponent space equals space integral straight e to the power of 2 straight x end exponent space cos space 3 straight x space dx space plus straight c
or    ye to the power of 2 straight x end exponent space equals space fraction numerator 1 over denominator square root of 4 plus 9 end root end fraction straight e to the power of 2 straight x end exponent space cos space open parentheses 3 straight x minus tan to the power of negative 1 end exponent 3 over 2 close parentheses plus straight c
                                              open square brackets because space space space integral straight e to the power of ax cos space bxdx space equals space fraction numerator 1 over denominator square root of straight a squared plus straight b squared end root end fraction straight e to the power of ax cos space open parentheses bx minus tan to the power of negative 1 end exponent straight b over straight a close parentheses close square brackets
therefore space space space space space space space straight y space equals fraction numerator 1 over denominator square root of 13 end fraction cos space open parentheses 3 straight x minus tan to the power of negative 1 end exponent 3 over 2 close parentheses plus straight c space straight e to the power of negative 2 straight x end exponent
which is required solution. 

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