-->

Differential Equations

Question
CBSEENMA12033181

Solve the following differential equation:
dy over dx space plus 2 space straight y space tan space straight x space equals space sin space straight x

Solution
The given differential equation is
                 dy over dx plus 2 space straight y space tanx space equals space sin space straight x
Comparing it with dy over dx plus Py space equals space straight Q comma we get,
                   straight P space equals space 2 space tanx space space space straight Q space equals space sin space straight x
therefore space space space space integral straight P space dx space equals space 2 space integral space tan space straight x space dx space equals space minus 2 space log space cosx space space equals space log space left parenthesis cosx right parenthesis squared
therefore space space space space space space space space space space straight I. straight F. space equals space straight e to the power of integral straight P space dx end exponent space equals space straight e to the power of log space left parenthesis cosx space right parenthesis to the power of negative 2 end exponent end exponent space equals space left parenthesis cos space straight x right parenthesis to the power of negative 2 end exponent space equals space fraction numerator 1 over denominator cos squared straight x end fraction
therefore space space space space space space solution space of space differential space equation space is
                           straight y. space fraction numerator 1 over denominator cos squared straight x end fraction space equals space integral sin space straight x. space space fraction numerator 1 over denominator cos squared straight x end fraction dx plus straight c
                                          open square brackets therefore space space space straight y space straight e to the power of integral straight P space dx end exponent space equals space integral straight Q space straight e to the power of integral straight P space dx end exponent dx plus straight c close square brackets
or                 fraction numerator straight y over denominator cos squared straight x end fraction space equals space integral space tanx space secx space dx plus straight c
or           fraction numerator straight y over denominator cos squared straight x end fraction space equals space secx plus straight c
or           straight y equals cosx plus straight c space cos squared straight x
which is required solution. 

Some More Questions From Differential Equations Chapter