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Differential Equations

Question
CBSEENMA12033154

Solve :  dy over dx plus straight y space equals space sin space straight x comma space space left parenthesis straight x space element of space straight R right parenthesis

Solution

The given differential equation is dy over dx plus straight y space equals space sin space straight x
Comparing it with dy over dx plus straight P space straight y space equals space straight Q comma space space space we space get comma space space space straight P space equals space 1 comma space space straight Q space equals space sin space straight x
therefore space space space integral straight P space dx space equals space integral 1 space dx space equals space straight x. space space space straight I. straight F. space equals space straight e to the power of integral straight P space dx end exponent space equals space straight e to the power of straight x
therefore space space space solution of differential equation is
                     straight y space. straight e to the power of straight x space equals space integral space sinx. space straight e to the power of straight x space dx space plus space straight c space or space space straight y space. straight e to the power of straight x space equals space fraction numerator 1 over denominator square root of 1 plus 1 end root end fraction straight e to the power of straight x space sin space open parentheses straight x minus tan to the power of negative 1 end exponent 1 over 1 close parentheses plus straight c
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets because space space integral straight e to the power of ax space sin space bx space equals space fraction numerator 1 over denominator square root of straight a squared plus straight b squared end root end fraction straight e to the power of ax space sin space open parentheses bx minus tan to the power of negative 1 end exponent straight b over straight a close parentheses close square brackets
or space space space straight y space equals space fraction numerator 1 over denominator square root of 2 end fraction sin space open parentheses straight x minus straight pi over 4 close parentheses plus space straight c space straight e to the power of negative straight x end exponent

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