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Vector Algebra

Question
CBSEENMA12033033

Find the general solution of each of the following equations:
dy over dx equals fraction numerator straight y left parenthesis straight x squared minus 1 right parenthesis over denominator straight x left parenthesis straight y squared minus 1 right parenthesis end fraction





Solution

The given differential equation is
             dy over dx space equals space fraction numerator straight y left parenthesis straight x squared minus 1 right parenthesis over denominator straight x left parenthesis straight y squared minus 1 right parenthesis end fraction
Separating the variables, we get,
                          fraction numerator straight y squared minus 1 over denominator straight y end fraction dy space equals space fraction numerator straight x squared minus 1 over denominator straight x end fraction dx
therefore space space space space space space integral open parentheses straight y squared over straight y minus 1 over straight y close parentheses dy space equals space integral open parentheses straight x squared over straight x minus 1 over straight x close parentheses dx
or          integral open parentheses straight y minus 1 over straight y close parentheses dy space equals space integral open parentheses straight x minus 1 over straight x close parentheses dx
or        straight y squared over 2 minus log space open vertical bar straight y close vertical bar space equals space straight x squared over 2 minus log space open vertical bar straight x close vertical bar space plus space straight c
is the required solution.