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Complex Numbers And Quadratic Equations
If (1 – p) is a root of quadratic equation x^{2} +px + (1p)=0 , then its roots are
0, 1
1, 2
0, 1
1, 1
C.
0, 1
Since (1  p) is the root of quadratic equation
x2 + px + (1  p) = 0 ........ (i)
So, (1  p) satisfied the above equation
∴ (1  p)^{2} + p(1  p) + (1  p) = 0
(1  p)[1  p + p + 1] = 0 (1  p)(2) = 0
⇒ p = 1 On putting this value of p in equation (i)
x^{2} + x = 0
⇒ x(x + 1) = 0 ⇒ x = 0, 1
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