The conjugate of a complex number is . Then the complex number is

C.

Question

The conjugate of a complex number is . Then the complex number is

Solution

C.

If the roots of the equation bx^{2}+ cx + a = 0 be imaginary, then for all real values of x, the expression 3b^{2}x^{2} + 6bcx + 2c^{2} is

The quadratic equations x^{2} – 6x + a = 0 and x^{2} – cx + 6 = 0 have one root in common. The other roots of the first and second equations are integers in the ratio 4 : 3. Then the common root is

All the values of m for which both roots of the equations x^{2} − 2mx + m^{2} − 1 = 0 are greater than −2 but less than 4, lie in the interval

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