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Binomial Theorem

Question
CBSEENMA11015542

hyperbola passes through the point P(√2, √3) and has foci at (± 2, 0). Then the tangent to this hyperbola at P also passes through the point

  • left parenthesis negative square root of 2 comma space minus square root of 3 right parenthesis
  • left parenthesis 3 square root of 2 space comma space 2 square root of 3 right parenthesis
  • left parenthesis 2 square root of 2 space comma 3 space square root of 3 right parenthesis
  • left parenthesis square root of 3 comma square root of 2 right parenthesis

Solution

C.

left parenthesis 2 square root of 2 space comma 3 space square root of 3 right parenthesis

Equation of hyperbola is straight x squared over straight a squared minus straight y squared over straight b squared space equals space 1
foci is (±2, 0) hence ae = 2, ⇒ a2e2 = 4

b2 = a2(e2 – 1)
∴ a2 + b2 = 4
Hyperbola passes through √2,√3
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