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Sequences And Series

Question
CBSEENMA11015494

The x-coordinate of the incentre of the triangle that has the coordinates of mid points of its sides as (0, 1) (1, 1) and (1, 0) is

  • 2 plus square root of 2
  • 2 minus square root of 2
  • 1 plus square root of 2
  • 1 minus square root of 2

Solution

B.

2 minus square root of 2

Given mid points of sides of a triangle are (0,1) (1,1) and (1,0). Plotting these points on a graph and make a triangle.

straight x minus coordinate space space equals space fraction numerator ax subscript 1 space plus bx subscript 2 plus cx subscript 3 over denominator straight a plus straight b plus straight c end fraction

space equals space fraction numerator 2 space straight x space 2 space plus 2 square root of 2 space straight x 0 space plus 2 straight x 0 over denominator 2 plus 2 plus 2 square root of 2 end fraction
space equals space fraction numerator 4 over denominator 4 plus 2 square root of 2 end fraction space equals space fraction numerator 2 over denominator 2 plus square root of 2 end fraction space equals space 2 minus square root of 2