Question
The image of line 
in the plane 2x-y+z+3 =0 is the line
Solution
A.
Here, plane and line are parallel to each other. Equation of normal to the plane through the point (1,3,4) is
Any point in this normal is (2jk+2, -k+3,4+k)
Then, 
lies on the plane.
hence, point through which this image pass is
(2k+1,3-k,4+k)
i.e., (2(-2) + 1, 3+2, 4-2) = (-3,5,2)
Hence equation of image line is
