Question
The locus of the foot of perpendicular drawn from the centre of the ellipse x2+3y2 =6 on any tangent to it is
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(x2-y2)2 = 6x2+2y2
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(x2-y2)2 = 6x2 -2y2
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(x2+y2)2 = 6x2+2y2
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(x2+y2)2 = 6x2-2y2
Solution
C.
(x2+y2)2 = 6x2+2y2
Equation of ellipse is,
The slope of the perpendicular drawn from the centre (0,0) to (h,k) is k/h.
Since, both the lines are perpendicular,