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Statistics

Question
CBSEENMA11015265

Find the median of the data: 111, 129, 143, 118, 120, 125, 170, 162.

Solution

The data in ascending order is:
111, 118, 120, 125, 129, 143, 162, 170                                        ...(i)
                          N = 8 (Even)
rightwards double arrow                 Median = fraction numerator straight T subscript begin display style straight N over 2 end style end subscript plus straight T subscript begin display style straight N over 2 end style plus 1 end subscript over denominator 2 end fraction
                             straight T subscript straight N over 2 end subscript space equals space straight T subscript 8 over 2 end subscript space equals space straight T subscript 4 space equals space 125                       [From (i)]
                       space straight T subscript straight N over 2 plus 1 end subscript space equals space straight T subscript 8 over 2 plus 1 end subscript space equals space straight T subscript 5 space equals space 129                     [From (i)]
∴                       Median = space space fraction numerator 125 plus 129 over denominator 2 end fraction equals 127