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The equation of the parabola is 4a = 12 or a = 3 Focus S is (0, a) (0, 3) OS = 3 LL' = length of the latus rectum = 4a = 12 Hence, area of - Wired Faculty

Binomial Theorem

Question

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Find the area of the triangle formed by the lines joining the vertex of the parabola x² = 12y to the ends of the latus rectum.

Solution

The equation of the parabola is $straight x squared equals 12 straight y.$
$rightwards double arrow$ 4a = 12 or a = 3
Focus S is (0, a) $left right arrow$ (0, 3)
$rightwards double arrow$ OS = 3
LL' = length of the latus rectum
= 4a = 12
Hence, area of $ΔOLL apostrophe space equals space 1 half left parenthesis LL apostrophe right parenthesis space cross times space OS$
$equals 1 half cross times 12 cross times 3 space equals space 18 space square space units.$

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Binomial Theorem

Find the area of the triangle formed by the lines joining the vertex of the parabola x² = 12y to the ends of the latus rectum.

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For Daily Free Study Material Join wiredfaculty

Binomial Theorem

Find the area of the triangle formed by the lines joining the vertex of the parabola x2 = 12y to the ends of the latus rectum.

Some More Questions From Binomial Theorem Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Find the area of the triangle formed by the lines joining the vertex of the parabola x² = 12y to the ends of the latus rectum.