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Binomial Theorem

Question
CBSEENMA11015182

The arch given below is in form of a semi-ellipse. It is 8 m wide and its height at the centre is 2 m. Find the height of the arch at a distance of 1.5 m from one end.
                                      

Solution

Width of the elliptical arch = 8 m   rightwards double arrow  AA' = 8m rightwards double arrow 2a = 8m rightwards double arrow a = 4
Height at the centre = 2m  rightwards double arrow      OB = 2m rightwards double arrow   b = 2
∴ the equation of ellipse is straight x squared over 16 plus straight y squared over 4 equals 1                                     ...(i)
                                   AP space equals space 1.5 space straight m space rightwards double arrow space OP space equals space OA minus AP space equals space 4 minus 1.5 equals 2.5 space straight m
Let the height at P be h.
∴   Coordinates of L are (2.5, h)
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#6 {main}</pre>
rightwards double arrow                                    straight h squared equals fraction numerator 16 minus 6.25 over denominator 4 end fraction equals fraction numerator 9.75 over denominator 4 end fraction equals 2.44 space left parenthesis Approx right parenthesis
Hence, straight h equals square root of 2.44 end root space equals space 1.56 space straight m space left parenthesis Approx. right parenthesis

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