Sponsor Area

Sequences And Series

Question
CBSEENMA11014972

Show that A (6, 10, 10), B (1, 0, -5) and C (6, -10, 0) are the vertices of a right angled triangle.

Solution
WiredFaculty
Using distance formula, we have
               WiredFaculty
                             equals square root of left parenthesis 5 right parenthesis squared plus left parenthesis 10 right parenthesis squared plus left parenthesis 15 right parenthesis squared end root space equals space square root of 25 plus 100 plus 225 end root space equals space square root of 350
                                            
                        WiredFaculty
                              equals space square root of left parenthesis negative 5 right parenthesis squared plus left parenthesis 10 right parenthesis squared plus left parenthesis negative 5 right parenthesis squared end root space equals space square root of 25 plus 100 plus 25 end root space equals space square root of 150                                   
                     space space space CA equals square root of left parenthesis straight x subscript 3 minus straight x subscript 1 right parenthesis squared plus left parenthesis straight y subscript 3 minus straight y subscript 1 right parenthesis squared plus left parenthesis straight z subscript 3 minus straight z subscript 1 right parenthesis squared end root
                     space space space space space space space space space equals space square root of left parenthesis 0 right parenthesis squared plus left parenthesis negative 20 right parenthesis squared plus left parenthesis negative 10 right parenthesis squared end root space equals space square root of 0 plus 400 plus 100 end root space equals space square root of 500
   Now,    WiredFaculty
Hence, triangle ABC is a right angled triangle.