A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed. find the probability that the sum of numbers that turn up is 3.

The coin has 1 marked on on face and 6 on the other. Let H = 1 or T = 6. The coin and die are tossed together.
  S = {(H,1), (H,2), (H,3), (H,4), (H,5), (H,6), (T,1), (T,2), (T,3), (T,4), (T,5), (T,6)}
 S = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
     n(S) = 12
Event A: A total of 3 is obtained.
            A = {(1, 2)}    n(A) = 1
Hence,