Principle Of Mathematical Induction

Question
CBSEENMA11014314

Prove that:
2 cosA sinB = sin (A + B) - sin (A - B)




Solution

R.H.S. = sin (A + B) - sin (A - B)
          = [sinA cosB + cosA sinB] - [sinA cosB - cosA sinB]
          = 2 cosA sinB = L.H.S.
Hence,   2 cosA sinB = [sin (A + B) - sin (A - B)]

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