Principle Of Mathematical Induction

Question
CBSEENMA11014347

Prove that:

straight s left parenthesis straight s minus straight a right parenthesis space tan straight A over 2 equals straight capital delta

Solution

L.H.S. = straight s left parenthesis straight s minus straight a right parenthesis square root of fraction numerator left parenthesis straight s minus straight b right parenthesis left parenthesis straight s minus straight c right parenthesis over denominator straight s left parenthesis straight s minus straight a right parenthesis end fraction end root equals square root of straight s left parenthesis straight s minus straight a right parenthesis left parenthesis straight s minus straight b right parenthesis left parenthesis straight s minus straight c right parenthesis end root equals straight capital delta equals straight R. straight H. straight S.

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