Principle Of Mathematical Induction

Question
CBSEENMA11014292

Prove that:
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#1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php(56): mkdir('/home/config_ad...', 493)
#2 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/FolderTreeStorageAndCache.class.php(110): com_wiris_util_sys_Store->mkdirs()
#3 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/RenderImpl.class.php(231): com_wiris_plugin_impl_FolderTreeStorageAndCache->codeDigest('mml=<math xmlns...')
#4 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/TextServiceImpl.class.php(59): com_wiris_plugin_impl_RenderImpl->computeDigest(NULL, Array)
#5 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/service.php(19): com_wiris_plugin_impl_TextServiceImpl->service('mathml2accessib...', Array)
#6 {main}</pre>



Solution
space space space space tan open parentheses straight pi over 2 plus straight x close parentheses space equals space fraction numerator sin open parentheses begin display style straight pi over 2 plus straight x end style close parentheses over denominator cos open parentheses begin display style straight pi over 2 plus straight x end style close parentheses end fraction space equals space fraction numerator cosx over denominator negative sinx end fraction equals negative cotx
Hence,   tan open parentheses straight pi over 2 plus straight x close parentheses space equals space minus cot space straight x

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