Question
4 boys and 3 girls are to sit around a round table. In how many ways can this be done so that no two girls sit together.
Solution
Let the boys sit around the round table.
Number of arrangements = (4 - 1)! =3! = 6 ...(i)
There are 4 seats for the girls and there are 3 girls.
Number of arrangements = ...(ii)
∴ Total number of permutations when no two girls are together = 6 x 24 = 144