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Permutations And Combinations
Question
In how many ways can 4 red, 3 yellow and 2 green balls be arranged in a row if the balls of the same colour is indistinguishable?
Solution
Total number of balls = ![]()
n = 9
Number of red balls = 4
p = 4
Number of yellow balls = 3
q = 3
Number of green balls = 2
r = 2
∴ The number of permutations of balls:
![]()
= 9 x 4 x 7 x 5 = 1260.
Some More Questions From Permutations and Combinations Chapter
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