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Event 1: A coin is tossed and the outcomes recorded. Number of outcomes m = 2 Event 2: The coin is tossed again and the outcomes recorded. Number of outcomes n = 2 Event 3: The coin is tossed third time and the outcomes recorded. Number of outcomes p = 2 ∴ By fundamental principle of counting, the total number of outcomes recorded = - Wired Faculty

Permutations And Combinations

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A coin is tossed 3 times and the outcomes are recorded. How many possible outcomes are there?

Solution

Event 1: A coin is tossed and the outcomes recorded.

Number of outcomes $open curly brackets straight H. space straight T close curly brackets space equals space 2$
$rightwards double arrow$ m = 2
Event 2: The coin is tossed again and the outcomes recorded.
Number of outcomes $open curly brackets straight H comma space straight T close curly brackets space equals space 2$
$rightwards double arrow$ n = 2
Event 3: The coin is tossed third time and the outcomes recorded.
Number of outcomes $open curly brackets straight H comma space straight T close curly brackets space equals space 2$
$rightwards double arrow$ p = 2
∴ By fundamental principle of counting, the total number of outcomes recorded
= $straight m cross times straight n cross times straight p space equals space 2 cross times 2 cross times 2 equals 8$

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Permutations And Combinations

A coin is tossed 3 times and the outcomes are recorded. How many possible outcomes are there?

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