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Question
CBSEENMA11012992

Find the value of the following :


space space space space space space space space space space space space space space space open square brackets straight i to the power of 19 plus open parentheses 1 over straight i close parentheses to the power of 25 close square brackets squared

Solution
space space space space space space space space space space space space space open square brackets straight i to the power of 19 plus open parentheses 1 over straight i close parentheses to the power of 25 close square brackets squared    = space space space space space space space space space space space space open square brackets straight i to the power of 19 plus 1 over straight i to the power of 25 close square brackets squared equals open square brackets open parentheses straight i to the power of 19. straight i cubed close parentheses plus 1 over straight i to the power of 25. straight i cubed over straight i cubed close square brackets

              WiredFaculty
                                = 4i6 = 4i4 . i2 = 4i2 = 4(-1) = -4               ( i4 = 1