Prove the following by using the principle of mathematical induction for all ![]()
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Let P(n): ![]()
I. For n = 1,
P(1) : 1 = ![]()
∴ P(1) is true
II. Let the statement be true for n = m, ![]()
P(m) : 1 + 3 + 5 + .................... + (2m - 1) = m2 ...(i)
III. For n = m + 1,
P(m + 1) : 1 + 3 + 5 + .......... + [2 (m+1) - 1] = (m + 1)2
or 1 + 3 + 5 + ........... + (2m - 1) + (2m + 1) = (m + 1)2
From (i),
![]()
∴ ![]()
![]()
∴ P (m + 1) is true.
∴ P(m) is true.
is true.
Hence, by the principal of mathematical induction, P(n) is true for all ![]()



