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Trigonometric Functions

Question
CBSEENMA11013626

Find the values of x and y when

(x2--x, y-3y+2)=(0, 0)

Solution

(x-x, y-3y+2) = (0, 0)
rightwards double arrow        x-x = 0 or x(x-1)=0 or x = 0, 1
and y-3y+2 = 0 or (y-1) (y-*2) = 0 or y = 1, 2
Hence,  x = 0, x = 1, y = 1, y = 2