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Principle Of Mathematical Induction

Question
CBSEENMA11013518

Solve the equation:

WiredFaculty

Solution

Given equation is:
tan left parenthesis straight x plus straight a right parenthesis space. space tan left parenthesis straight x plus straight b right parenthesis space plus space tan left parenthesis straight x plus straight b right parenthesis. space tan left parenthesis straight x plus straight c right parenthesis space plus space tan left parenthesis straight x plus straight c right parenthesis space tan space left parenthesis straight x plus straight a right parenthesis space equals space 1
tan space left parenthesis straight x plus straight a right parenthesis space tan space left parenthesis straight x plus straight b right parenthesis space plus tan space left parenthesis straight x plus straight b right parenthesis space tan space left parenthesis straight x plus straight c right parenthesis space equals space 1 minus tan space left parenthesis straight x plus straight c right parenthesis space tan space left parenthesis straight x plus straight a right parenthesis
WiredFaculty
rightwards double arrow    tan space left parenthesis straight x plus straight b right parenthesis space open curly brackets fraction numerator tan space left parenthesis straight x plus straight a right parenthesis space plus space tan space left parenthesis straight x plus straight c right parenthesis over denominator 1 minus tan space left parenthesis straight x plus straight a right parenthesis space tan space left parenthesis straight x plus straight c right parenthesis end fraction close curly brackets space equals space 1
rightwards double arrow    tan space left parenthesis straight x plus straight b right parenthesis space tan space open curly brackets open parentheses straight x plus straight a close parentheses plus left parenthesis straight x plus straight c right parenthesis close curly brackets space equals space 1
rightwards double arrow     tan space left parenthesis straight x plus straight a plus straight x plus straight c right parenthesis space equals space fraction numerator 1 over denominator tan space left parenthesis straight x plus straight b right parenthesis end fraction           rightwards double arrow  tan space left parenthesis 2 straight x plus straight a plus straight c right parenthesis space equals space cot space left parenthesis straight x plus straight b right parenthesis
rightwards double arrow     tan space left parenthesis 2 straight x plus straight a plus straight c right parenthesis space equals space tan open parentheses straight pi over 2 minus left parenthesis straight x plus straight b right parenthesis close parentheses       rightwards double arrow 2 straight x plus straight a plus straight c space equals space nπ space plus space straight pi over 2 minus left parenthesis straight x plus straight b right parenthesis comma space straight n space element of space straight Z
rightwards double arrow     2 straight x plus straight a plus straight c space equals space nπ space plus space straight pi over 2 minus straight x minus straight b comma space straight n element of straight Z     rightwards double arrow   space space space 3 straight x space equals space nπ plus straight pi over 2 minus straight b minus straight a minus straight c
rightwards double arrow     3 straight x space equals space nπ space plus space straight pi over 2 minus left parenthesis straight a plus straight b plus straight c right parenthesis comma space straight n space element of space straight Z       rightwards double arrow    straight x space equals space nπ over 3 plus straight pi over 6 minus open parentheses fraction numerator straight a plus straight b plus straight c over denominator 3 end fraction close parentheses comma space straight n space element of space straight Z