If
and
where
and
find the
value of
State the quadrant in which
terminates.
![]()
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We know that ![]()
![]()
![]()
[∵
is -ve as
lies in IInd quadrant]

Now,
and ![]()
![]()
We know that
in Ist and IIIrd quadrant.
∴
lies in 1st quadrant.



