Limits And Derivatives

  • Question
    CBSEENMA11013238

    Find  space space space space space space space space space space space space space space space space space space space space dy over dx space space if space left parenthesis straight i right parenthesis space straight y space space equals space fraction numerator 1 minus square root of straight x over denominator 1 plus square root of straight x end fraction

    Solution

    space space space space space space space space space space space space space space space fraction numerator negative 1 over denominator square root of straight x left parenthesis 1 plus square root of straight x right parenthesis squared end fraction

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