Sponsor Area
Relations And Functions
(i) A = 
and x is a root of quadratic equation x2 -3x -10 = 0}
Now, x2 -3x -10 = 0 
(x-5) (x+2) = 0
x=5, -2 which are both integers.
Hence, A = {-2, 5}
(ii) B= {x :x 
, -5 < x-2 < 5}
Now, -5 < x-2 < 5
-3 < x < 7
x is a natural number between -3 and 7 (exclusive).
Hence, B = {1, 2, 3, 4, 5, 6}
(iii) C = {x : x is an odd prime number less than 30}
x = 3, 5, 7, 11, 13, 17, 19, 23, 29
Hence C = { 3, 5, 7, 11, 13, 17, 19, 23, 29}
Some More Questions From Relations and Functions Chapter
i9 + i19
3(7 + i7) + i(7 + i7)
Express each of the complex number given in the form of a + ib.
(1 - i) - (-1 + i6)
(1 - i) - (-1 + i6)
Express each of the complex number given in the form of a + ib.
(1 - i)4
(1 - i)4
Find the multiplicative inverse of
- i
- i
Sponsor Area
Mock Test Series
Mock Test Series