Sponsor Area

Limits And Derivatives

Question
CBSEENMA11013113

Evaluate  WiredFaculty


Solution
space space space space space space space space space space space space space space space space space space limit as straight x rightwards arrow 4 of fraction numerator 4 straight x plus 3 over denominator straight x minus 2 end fraction equals fraction numerator 4 left parenthesis 4 right parenthesis plus 3 over denominator 4 minus 2 end fraction equals fraction numerator 16 plus 3 over denominator 2 end fraction equals 19 over 2

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