Question
Find the sum to n terms of the following series.

Solution
Here, [nth term of 1, 2, 3,......]
[nth term of 2, 3, 4,.....]
[nth term of 3, 4, 5......]
= [1 + (n - 1). 1] [2 + (n - 1). 1] [3 + (n - 1) .1]
=
Let denote the sum of n terms of series, then
=
=