Limits And Derivatives

  • Question
    CBSEENMA11013148

    Evaluate space space space space space limit as straight x rightwards arrow 0 of fraction numerator sin space ax over denominator bx end fraction.

    Solution

    space space space space space space space space space space limit as straight x rightwards arrow 0 of fraction numerator sin space ax over denominator bx end fraction equals 1 over straight b limit as straight x rightwards arrow 0 of fraction numerator sin space ax over denominator ax end fraction xa equals straight a over straight b semicolon fraction numerator sin space ax over denominator ax end fraction                                   [∵ xrightwards arrow0rightwards double arrowaxrightwards arrow0]

       space space space space space space space space space space space space space space equals straight a over straight b.1 equals straight a over straight b

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