Relations and Functions

Relations and Functions

Question

Find the values of x and y, if.

(2x + y - 5) + (3x - 2y - 4) i = 0

Answer

(2x + y - 5) + (3x - 2y - 4) i = 0
Equating real and imaginary parts, we get
Re (z) : 2x + y - 5 = 0                                                                       ...(i)
Im (z) : 3x - 2y -4 = 0                                                                       ...(ii)
 
Multiplying (1) b y 3 and (ii) by 2, we get\
6x + 3y - 15 = 0                                                                                ...(iii)
6x - 4y - 8  = 0                                                                                 ...(iv)
Subtracting (iv) from (iii), we get
              7y - 7 = 0                           rightwards double arrow                        y = 1
Using in (i), we get
              2x + 1 - 5 = 0                     rightwards double arrow                          x = 2
Hence,   x = 2 and y = 1

    

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