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Permutations And Combinations
Question
Let the sum of n, 2n, 3n terms of an A.P., be S1, S2, S3, respectively, show that ![]()
Solution
Let a be the first term and d be the common difference.
∴
...(i)
...(ii)
... (iii)
Subtracting (i) from (ii), we get
![]()
![]()
[B using (3)]
Hence, ![]()
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