-
Call Us
+91 8076753736 -
Send us an Email
[email protected]
Relations And Functions
Find the square root of the following complex numbers :
Let ...(i)
Squaring both sides, we get
x2 - y2 + 2xyi ...(ii)
(∵ i2 = -1)
Equating real and imaginary parts, we get
x2 - y2 = 1 ...(iii)
2xy = ...(iv)
4x2y2 = 16(3) = 48
Now, (x2 + y2)2 = (x2 - y2)2 +4x2y2
(x2 + y2)2 = 1 + 48 = 49
x2 + y2 = 7
But, x2 + y2 -7 for x. y R
x2 + y2 = 7 ...(v)
Also, x2 - y2 = 1
Adding, we get 2x2 = 8 x2 = 4 x = 2
When x = 2, from (iv), y =
Putting in (i), we get
or
Hence,
Sponsor Area
i9 + i19
3(7 + i7) + i(7 + i7)
Express each of the complex number given in the form of a + ib.
(1 - i) - (-1 + i6)
Express each of the complex number given in the form of a + ib.
(1 - i)4
Find the multiplicative inverse of
- i
Sponsor Area