Surface Areas And Volumes

Question

Wired Faculty App

A bucket is in the form of a frustum of a cone and its can hold 28.49 litres of water. If the radii of its circular ends are 28 cm and 21 cm, find the height of the bucket. $[use π = \frac{22}{7}]$

Solution

Here, R = 28 cm and r = 21 cm, we need to find h

Volume of frustum = 28.49 L = 28.49 x 1000 cm³ = 28490 cm³

Now, volume of frustum = $\frac{πh}{3} (R^{2} + Rr + r^{2})$

$\Rightarrow \frac{22 h}{7 x 3} (28^{2} + 28 x 21 + 21^{2}) = 28490 \Rightarrow \frac{22}{21} h x 1813 = 28490 \Rightarrow h = \frac{28490 x 21}{22 x 1813} = 15 cm$

Hence the height of bucket is 15 cm.

Sponsor Area

For Daily Free Study Material Join wiredfaculty

Surface Areas And Volumes

A bucket is in the form of a frustum of a cone and its can hold 28.49 litres of water. If the radii of its circular ends are 28 cm and 21 cm, find the height of the bucket. $[use π = \frac{22}{7}]$

Some More Questions From Surface Areas and Volumes Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction

For Daily Free Study Material Join wiredfaculty

Surface Areas And Volumes

A bucket is in the form of a frustum of a cone and its can hold 28.49 litres of water. If the radii of its circular ends are 28 cm and 21 cm, find the height of the bucket. use π = 227

Some More Questions From Surface Areas and Volumes Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A bucket is in the form of a frustum of a cone and its can hold 28.49 litres of water. If the radii of its circular ends are 28 cm and 21 cm, find the height of the bucket. $[use π = \frac{22}{7}]$