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Arithmetic Progressions

Question
CBSEENMA10009764

The sum of the 2nd and the 7th terms of an AP is 30. If its 15th term is 1 less than twice its 8th term, find the AP.

Solution

The sum of the  2nd and the 7th terms of an AP is 30

a + d + a + 6d = 302a + 7d = 3015 th term is 1 less than twice the 8th terma + 14d = 2 (a + 7d ) -1a + 14d = 2a + 14d -1a = 1Now,  2 x 1 + 7d = 30d = 4AP; 1, 5, 9,.................