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Coordinate Geometry

Question

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Find the ratio in which the line segment joining the points A(3,- 3) and B(- 2, 7) is divided by x-axis. Also find the coordinates of the point of division

Solution

Point P lies on X-axis so it's coordinate is 0 ( Using section formula )

Let the ratio be k:1

Let the coordinate of the point be P(x,0)

As given A(3, -3) and B( -2,7)

$y = \frac{({my}_{2} + {ny}_{1})}{m + n} 0 = (\frac{k x 7 + 1 x (- 3)}{k + 1}) 0 x (k + 1) = 7 k - 3 0 = 7 k - 1 3 = 7 k k = \frac{3}{7} k : 1 = 3 : 7 x = (\frac{{mx}_{2} + {nx}_{1}}{m + n}) x = \frac{[(\frac{3}{7} x (- 2)) + (1 x 3)]}{(\frac{3}{7} + 1)} x = 1.5$

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Coordinate Geometry

Find the ratio in which the line segment joining the points A(3,- 3) and B(- 2, 7) is divided by x-axis. Also find the coordinates of the point of division

Some More Questions From Coordinate Geometry Chapter

Prove that the diagonals of a rectangle ABCD, with vertices A(2, -1), B(5, -1), C(5, 6) and D(2, 6), are equal and bisect each other.

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