Sponsor Area

Areas Related To Circles

Question
CBSEENMA10009761

In Figure 2, ABCD is a trapezium of area 24.5 sq. cm. In it, AD|| BC,  DAB = 90°, AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region.    Take π= 227                  

                     

Solution

         

  Area of a trapezium = 24.5 cm212 AD + BC X AB = 24.5 Cm212 10+4 X AB = 24.5AB = 3.5 cm     r= 3.5 cmAreao of quadrant = 14x π r2                                = 0.25 x  227 x 3.5 x 3.5                                      = 9.625 cm2 The area of shaded region = 24. 5 - 9.625                                          = 14.875 cm2