Question

In Figure 2, ABCD is a trapezium of area 24.5 sq. cm. In it, AD|| BC, $∠$ DAB = $90 °$ , AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region. $[Take π = \frac{22}{7}]$

Solution

$Area of a trapezium = 24.5 {cm}^{2} \frac{1}{2} [AD + BC] X AB = 24.5 {Cm}^{2} \frac{1}{2} [10 + 4] X AB = 24.5 AB = 3.5 cm r = 3.5 cm Areao of quadrant = \frac{1}{4} x π r^{2} = 0.25 x \frac{22}{7} x 3.5 x 3.5 = 9.625 {cm}^{2} The area of shaded region = 24 . 5 - 9.625 = 14.875 {cm}^{2}$

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In Figure 2, ABCD is a trapezium of area 24.5 sq. cm. In it, AD|| BC, $∠$ DAB = $90 °$ , AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region. $[Take π = \frac{22}{7}]$

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Areas Related To Circles

In Figure 2, ABCD is a trapezium of area 24.5 sq. cm. In it, AD|| BC, ∠ DAB = 90°, AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region. Take π= 227

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In Figure 2, ABCD is a trapezium of area 24.5 sq. cm. In it, AD|| BC, $∠$ DAB = $90 °$ , AD = 10 cm and BC = 4 cm. If ABE is a quadrant of a circle, find the area of the shaded region. $[Take π = \frac{22}{7}]$