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Circles

Question

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Two circles touch each other externally at P. AB is a common tangent to the circlestouching them at A and B. The value of $∠$ APB is

$30 °$

$45 °$

$60 °$

$90 °$

Solution

$90 °$

$TA = TP \Rightarrow ∠ TPA = ∠ TPA TB = TP \Rightarrow ∠ TBP = ∠ TPB ∴ ∠ TAP + ∠ TBP = ∠ TPA + ∠ TPB = ∠ APB ∠ TAP + ∠ TBP + ∠ APB = 180 ° [∵ Sum of . . . 180 °] ∴ ∠ APB + ∠ APB = 180 ° ∴ 2 ∠ APB = 180 ° ∴ ∠ APB = 90 °$

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Circles

Two circles touch each other externally at P. AB is a common tangent to the circlestouching them at A and B. The value of $∠$ APB is

$30 °$

$45 °$

$60 °$

$90 °$

Some More Questions From Circles Chapter

In the following figure, what are the angles of depression from the observing positions O₁ and O₂ of the object at A?

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For Daily Free Study Material Join wiredfaculty

Circles

Two circles touch each other externally at P. AB is a common tangent to the circlestouching them at A and B. The value of ∠ APB is 30° 45° 60° 90°

Some More Questions From Circles Chapter

In the following figure, what are the angles of depression from the observing positions O1 and O2 of the object at A?

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Two circles touch each other externally at P. AB is a common tangent to the circlestouching them at A and B. The value of $∠$ APB is

$30 °$

$45 °$

$60 °$

$90 °$

In the following figure, what are the angles of depression from the observing positions O₁ and O₂ of the object at A?