Two circular pieces of equal radii and maximum area, touching each otherare cut out from a rectangular card board of dimensions 14 cm x 7 cm. Find the area of the remaining card board.

$|Use π = \frac{22}{7}|$

Solution

Dimensions of the rectangle card board = 14 cm x 7 cm

Since, two circular pieces of equal radii and maximum area touching each other are cut from the rectangular card board, therefore, the diameter oa each of each circular pieces is $\frac{14}{2} = 7 cm$

$Radius of each circular piece = \frac{7}{2} cm . ∴ Sum of area of two circular pieces = 2 x π {[\frac{7}{2}]}^{2} = 2 x \frac{22}{7} x \frac{49}{4} = 77 {cm}^{2} Area of the remaining card board = Area of the card board - Area of the two circular pieces = 14 cm x 7 cm - 77 {cm}^{2} = 98 {cm}^{2} - 77 {cm}^{2} = 21 {cm}^{2}$

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Circles

Two circular pieces of equal radii and maximum area, touching each otherare cut out from a rectangular card board of dimensions 14 cm x 7 cm. Find the area of the remaining card board.

$|Use π = \frac{22}{7}|$

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For Daily Free Study Material Join wiredfaculty

Circles

Two circular pieces of equal radii and maximum area, touching each otherare cut out from a rectangular card board of dimensions 14 cm x 7 cm. Find the area of the remaining card board.Use π = 227

Some More Questions From Circles Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Two circular pieces of equal radii and maximum area, touching each otherare cut out from a rectangular card board of dimensions 14 cm x 7 cm. Find the area of the remaining card board.

$|Use π = \frac{22}{7}|$