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Arithmetic Progressions

Question
CBSEENMA10009731

Find the number of terms of the AP -12, -9, -6,... 12. If 1 is added toeach term of this AP, then find the sum of all terms of the AP thusobtained.

Solution

Given A.P., is  -12, -9, -6, ......,21

first term, a= -12

comman difference, d=3

Let 21 be the nth  of the A.P.21=a+(n-1)d 21 -12 +(n-1)x3 33= (n-1)x3 n=12Sum of the terms of the A.P. = S12  = n2 (2a + (n-1) d  )  = 122( -24 + 11 x 3)  = 54If 1 is added to each term of AP, the sum of all the terms of the new AP will increase by n, i.e.,12. sum of all the terms of the new AP = 54+12=66