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In a circle of radius 21 cm, an arc subtends an angle of $60 °$ at the centre.Find: (i) the length of the arc (ii) area of the sector formed by the arc.
$|Use π = \frac{22}{7}|$

Solution

The arc subtends an angle of 60 $°$

$60 ° at the centre . (i) l = \frac{θ}{360} x 2 πr = \frac{60 °}{360} x 2 x \frac{22}{7} x 21 = 22 cm . (ii) area of the sector = \frac{θ}{360} x {πr}^{2} = \frac{60 °}{360} x \frac{22}{7} x 21 x 21 {cm}^{2} = 231 {cm}^{2}$

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Circles

In a circle of radius 21 cm, an arc subtends an angle of $60 °$ at the centre.Find: (i) the length of the arc (ii) area of the sector formed by the arc.
$|Use π = \frac{22}{7}|$

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For Daily Free Study Material Join wiredfaculty

Circles

In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre.Find: (i) the length of the arc (ii) area of the sector formed by the arc. Use π = 227

Some More Questions From Circles Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

In a circle of radius 21 cm, an arc subtends an angle of $60 °$ at the centre.Find: (i) the length of the arc (ii) area of the sector formed by the arc.
$|Use π = \frac{22}{7}|$