A cubical block of side 10 cm is surmounted by a hemisphere. What is the largest diameter that the hemisphere can have ? Find the cost of painting the total surface area of the solid so formed, at the rate of Rs 5 per 100 sq. cm. [Use π =3.14]

Solution

Now,
Total surface area of the solid = Total surface area of the cube + curved surface area of the hemisphere - Area of the base of the hemisphere
= 6a² + 2πr² -πr²
= [ 6 x (10)² + 2 x 3.14 x (5)² - 3.14 x (5)²] cm²
= (600 +157 -78.5 ) cm²
= 678.5 cm²
Cost of painting = Rs 5 per 100 cm²
Therefore,
Cost of painting the solid = 678.5 x (5/100) = Rs. 33.90
Hence, the approximate cost of painting the solid so formed is Rs. 33.90

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Statistics

A cubical block of side 10 cm is surmounted by a hemisphere. What is the largest diameter that the hemisphere can have ? Find the cost of painting the total surface area of the solid so formed, at the rate of Rs 5 per 100 sq. cm. [Use π =3.14]

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