In Given figure, a tower AB is 20 m high and BC, its shadow on the ground, is m $20 square root of 3$ long. Find the sun's altitude.

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Solution

Let the sun's altitude be θ.

In ΔABC,

tan space straight theta space equals space AB over BC rightwards double arrow space space tan space straight theta space equals space fraction numerator 20 over denominator 20 square root of 3 end fraction rightwards double arrow space space tan space equals space fraction numerator 1 over denominator square root of 3 end fraction rightwards double arrow space tan space straight theta space equals space tan space 30 to the power of straight o rightwards double arrow space straight theta space equals space 30 to the power of straight o Hence comma space the space altitude space of space Sun space is space 30 to the power of straight o

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