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Home > Quadratic Equations

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Quadratic Equations

Question
CBSEENMA10009598
Wired Faculty App

Solve for x:
fraction numerator 1 over denominator left parenthesis straight x minus 1 right parenthesis left parenthesis straight x minus 2 right parenthesis end fraction plus fraction numerator 1 over denominator left parenthesis straight x minus 2 right parenthesis left parenthesis straight x minus 3 right parenthesis end fraction space equals 2 over 3 comma space straight x not equal to 1 comma 2 comma 3

Solution
Short Answer
fraction numerator 1 over denominator left parenthesis straight x minus 1 right parenthesis left parenthesis straight x minus 2 right parenthesis end fraction plus fraction numerator 1 over denominator left parenthesis x minus 2 right parenthesis left parenthesis x minus 3 right parenthesis end fraction equals 2 over 3
therefore fraction numerator left parenthesis straight x minus 3 right parenthesis plus left parenthesis straight x minus 1 right parenthesis over denominator left parenthesis straight x minus 1 right parenthesis left parenthesis straight x minus 2 right parenthesis left parenthesis straight x minus 3 right parenthesis end fraction space equals 2 over 3
therefore fraction numerator straight x minus 3 plus straight x minus 1 over denominator left parenthesis straight x squared minus 2 straight x minus straight x plus 2 right parenthesis left parenthesis straight x minus 3 right parenthesis end fraction space equals 2 over 3
therefore fraction numerator 2 straight x minus 4 over denominator left parenthesis straight x squared minus 3 straight x plus 2 right parenthesis left parenthesis straight x minus 3 right parenthesis end fraction space equals space 2 over 3
therefore fraction numerator 2 straight x minus 4 over denominator straight x cubed minus 3 straight x squared minus 3 straight x squared plus 9 straight x plus 2 straight x minus 6 end fraction space equals 2 over 3
therefore space fraction numerator 2 straight x minus 4 over denominator straight x cubed minus 6 straight x squared plus 11 straight x minus 6 end fraction space equals 2 over 3
therefore 6 straight x minus 12 equals 12 straight x cubed minus 12 straight x squared plus 22 space straight x minus 12
therefore 2 straight x cubed minus 12 straight x squared plus 16 straight x equals 0
therefore 2 straight x left parenthesis straight x squared minus 6 straight x plus 8 right parenthesis space equals 0
therefore left parenthesis straight x squared minus 6 straight x plus 8 right parenthesis space equals 0
straight x squared minus 4 straight x minus 2 straight x plus 8 space equals 0
straight x left parenthesis straight x minus 4 right parenthesis minus 2 left parenthesis straight x minus 4 right parenthesis equals 0
therefore space left parenthesis straight x minus 4 right parenthesis left parenthesis straight x minus 2 right parenthesis space equals 0
straight x equals 4 space or space straight x equals 2

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Some More Questions From Quadratic Equations Chapter

Represent the following problem situations in the form of quadratic equations:
The product of two consecutive positive integers is 306. We need to find the integers.

Represent the following problem situations in the form of quadratic equations:
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