For what value of k will k+9, 2k-1 and 2k+7 are the consecutive terms of an A.P?
If k+9, 2k-1 and 2k+7 are the consecutive terms of A.P, then the common difference will be the same.
∴ (2k – 1) – (k + 9) = (2k + 7) – (2k – 1)
∴ k – 10 = 8
∴ k = 18
For what value of k will k+9, 2k-1 and 2k+7 are the consecutive terms of an A.P?
If k+9, 2k-1 and 2k+7 are the consecutive terms of A.P, then the common difference will be the same.
∴ (2k – 1) – (k + 9) = (2k + 7) – (2k – 1)
∴ k – 10 = 8
∴ k = 18
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a – 10, d = 10
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = –2, d = 0
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = 4, d = – 3
Write first four terms of the AP, when the first term a and the common difference d are given as follows:
a = – 1.25, d = – 0.25
For the following APs, write the first term and the common difference
3, 1, – 1, – 3, . . .
For the following APs, write the first term and the common difference
– 5, – 1, 3, 7, . . .
Mock Test Series