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Real Numbers

Question
CBSEENMA10009337

A bag contains 4 red and 6 black balls. A ballis taken out of the bag of random. Find the probability of setting a black ball.

Solution
No. of red balls = 4 No. of black balls = 6 Total no. of balls = 4 + 6 = 10 Let A be the favourable outcomes of setting a black ball, then, n(A) = 6 Therefore,
straight P left parenthesis straight A right parenthesis equals fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals 6 over 10 equals 3 over 5.

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