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Real Numbers

Question
CBSEENMA10009327

A jar contains 24 marbles, some are green and others are blue. If a marble is drawn at random from the jar, the probability that it is green is 2 over 3 Find the number of blue balls in the jar.

Solution

Total number of marbles in the jar = 24
i.e.    n(S) = 24
Let number of blue balls in the jar be x.
Then, the number of green balls in the jar = 24 – x Let A be the favourable outcomes of getting blue balls. Then
n(A) = x
Therefore, P(A) = fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals x over 24

Let B be favourable outcomes of getting green balls. Then
n(B) = 24 – x
Therefore,  P(B) = fraction numerator straight n left parenthesis straight B right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals fraction numerator 24 minus x over denominator 24 end fraction
According to the given condition :
                P(B) = 2 over 3
rightwards double arrow space space space space space space space space fraction numerator 24 minus straight x over denominator 24 end fraction equals 2 over 3
rightwards double arrow space space space space space space space space 3 left parenthesis 24 minus straight x right parenthesis space equals space 2 space straight x space 24
rightwards double arrow space space space space space space space space 72 minus 3 straight x equals 48
rightwards double arrow space space space space space space space space minus 3 straight x space equals space 48 minus 72
rightwards double arrow space space space space space space space space plus 3 straight x space equals space minus 24
rightwards double arrow space space space space space space space space space space space space straight x space equals space 8 space
Hence, the number of blue balls in the jar = 8.

Some More Questions From Real Numbers Chapter

Write the Sample Space when a coin is tossed.